PLAY · A-Level · AQA 7367

Turn the plane.

Three Further Maths instruments: move a complex number and watch its square and conjugate follow, feed a 2x2 matrix a shape to distort, and grow a polar curve petal by petal.

Argand diagram · z, z̄, z²

FIG. 01 · PURE B · COMPLEX NUMBERS
An Argand diagram showing a complex number with its conjugate and its square z Re Im
1.2
0.9

Or drag the accented point on the diagram. The dashed gold point is the conjugate; the pale point is z².

3
|z|
1.5
arg z (rad)
0.644
|z²| = |z|²
2.25
arg z² = 2arg z
1.288

cart 1.2 + 0.9i

mod-arg 1.5(cos 0.644 + i sin 0.644)

expo 1.5e^(0.644i)

z²   0.63 + 2.16i

Exam technique. Multiplying multiplies moduli and adds arguments — squaring therefore squares the modulus and doubles the argument, which is why z² swings round twice as fast as you drag. The n roots of any complex number always sit on one circle of radius |z|1/n, evenly spaced 2π/n apart, so once you have found one root you can write the rest down. Keep arg z in (−π, π] unless told otherwise.

Matrices · the determinant is an area

FIG. 02 · PURE F · MATRICES
A letter F in the unit square and its image under a two by two matrix M i M j x y

M

1
1
0
1

Load a standard one

det M = ad − bc
1
Area scale factor
1
Trace a + d
2
Real eigenvalues
1

Exam technique. The columns of M are exactly the images of i and j — read a transformation straight off the matrix rather than solving anything. |det M| is the area scale factor; a negative determinant means the orientation has flipped, so the F comes back mirror-image; and det M = 0 squashes the whole plane onto a line, which is precisely when M⁻¹ does not exist.

Polar curves · r = a + b cos nθ

FIG. 03 · PURE H · POLAR COORDINATES
A polar curve drawn out as the angle sweeps from zero θ = 0
1
1
1
360°
r at this θ
2
max r = a + b
2
min r = a − b
0
½∫r²dθ
4.71

Exam technique. Area in polars is ½∫r² dθ, never ∫y dx — and the limits are the angles where the curve starts and stops sweeping the region you want, which is usually where r = 0. AQA works with r ≥ 0, so switch that toggle off only to see what the negative-r branch would draw. Tangents parallel to the initial line come from dy/dθ = 0, where y = r sin θ.

Six real questions

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