PLAY · A-Level · AQA 7408

Launch it.

Fire a projectile with and without drag, split light through two slits, and watch a nucleus decay — three AQA A-Level Physics models you drive yourself.

Projectile motion, with the air switched on

FIG. 01 · MECHANICS · 3.4.1.3
Projectile trajectory Height against horizontal distance for a projectile, with and without air resistance. Numerical values are given in the readouts beside the graph. 0 HORIZONTAL DISTANCE x / m HEIGHT y / m NO DRAG MODELLED
30 m s⁻¹

Resolve it once: ux = u cos θ stays constant, uy = u sin θ is the only bit gravity touches.

45°

Complementary angles (30° and 60°) give identical range in a vacuum. Try it.

Air resistance

Modelled as a drag force proportional to v², opposing motion (k = 0.006 m⁻¹, a light ball). g = 9.81 m s⁻².

Range
Max height
Time of flight
Best angle

In the exam: the standard question gives you u and θ and expects the suvat treatment — vertical and horizontal motion handled separately, with time as the shared quantity. Range peaks at exactly 45° only when air resistance is ignored; switch drag on and the optimum angle drops, the path becomes asymmetric (steeper on the way down), and both range and time of flight fall. Saying "the trajectory is a parabola" is only worth a mark if you have already said "assuming air resistance is negligible".

Two slits, one screen, countable fringes

FIG. 02 · INTERFERENCE · 3.3.2.1
Double-slit interference pattern A simulated fringe pattern on a screen, with the corresponding intensity graph below it. Fringe spacing and path difference are given in the readouts. SCREEN · 36 mm WINDOW I₀ 0 −18 mm 0 +18 mm POSITION ON SCREEN y
550 nm

Monochromatic and coherent — a laser, or one slit illuminating both.

0.50 mm

Closer slits push the fringes further apart — w and s are inversely proportional.

2.0 m

Measure across ten fringes and divide — that is the required-practical trick for cutting uncertainty.

0.0 mm

Path difference at the probe is (s × y) / D.

Fringe spacing w
Path difference
Intensity
At the probe

In the exam: w = λD/s is on the data sheet, and you will be asked to rearrange it to find λ from measured fringes. The marks live in the reasoning: bright fringes where the path difference is a whole number of wavelengths (nλ, constructive, waves in phase); dark where it is an odd number of half-wavelengths ((n + ½)λ, destructive). The pattern only exists because the sources are coherent — constant phase difference and the same frequency.

Decay is exponential, and it never quite finishes

FIG. 03 · RADIOACTIVITY · 3.8.1.3
Radioactive decay curve Number of undecayed nuclei against time, on a linear or logarithmic scale. Values at the selected time are given in the readouts. N₀ 0 0 150 days TIME t / DAYS UNDECAYED NUCLEI N
10 days

Faint verticals mark successive half-lives: each one halves whatever is left, wherever you start.

0 days

Sample starts with N₀ = 1.00 × 10¹² undecayed nuclei.

Vertical scale

On the log axis the curve straightens: gradient = −λ. That is how a half-life is measured in practice.

Nuclei left
Fraction left
Decay constant λ
Activity A

In the exam: the two equations that do all the work are N = N₀e−λt and λT½ = ln 2, with activity A = λN. Watch the units — λ from a half-life in days must be converted to s⁻¹ before an activity in becquerel means anything. Decay is random and spontaneous: you cannot say which nucleus goes next, only that each has the same constant probability per unit time, which is exactly why the curve is exponential and never reaches zero.

Six real questions

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